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authorpriyanka2015-06-24 15:03:17 +0530
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+//Example5.21 // to design compensating network
+clc;
+clear;
+close;
+fH = 10 ; //k ohm // break frequency initiated by a zero
+fL = 1 ; //k ohm // break frequency initiated by a pole
+C = 0.02; // uF // we choose
+// loop gain of compensated network
+
+// ACom =(1+j(f/fH))/(1+j(f/fL))
+// fH = (1/2*pie*R1*C)
+// fL = (1/2*pie*(R1+R2)*C)
+R1 = (1/(2*3.14*C*fH));
+disp('The compensating first resistor R1 value is = '+string(R1)+' K ohm ');
+R2 = ((1)/(2*3.14*C*fL))-(R1);
+disp('The compensating second resistor R2 value is = '+string(R2)+' K ohm ');