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authorpriyanka2015-06-24 15:03:17 +0530
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+//Example5.16 // Determine the loop gain of compensated network
+clc;
+clear;
+close;
+
+C = 0.01*10^-6 ; // farad
+R = 15*10^3 ; // ohm
+F = 1*10^6 ; // Hz
+
+// the close loop gain of a compensated network is defined as
+// Ac = Acl*Acom ;
+
+//Acom = 1/(1+%(F/FL));
+
+FL = 1/(2*3.14*R*C);
+disp('FL = '+string(FL/1000)+' KHz '); // Round Off Error
+
+// Acom = 1/(1+%j(F/FL));
+// After putting value of F ,FL we get
+
+// Acom = 1/(1+%j(0.9)); // 1+%j(0.9) Rectangular Form where real part is 1 and imaginary part is 0.9
+
+// After converting rectangular from into polar from we get
+
+disp('Acom = [ magnitude = 0.68 angle = -47.7 degree ]');