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authorpriyanka2015-06-24 15:03:17 +0530
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+// To find the unknown impedence
+// Modern Electronic Instrumentation And Measurement Techniques
+// By Albert D. Helfrick, William D. Cooper
+// First Edition Second Impression, 2009
+// Dorling Kindersly Pvt. Ltd. India
+// Example 5-3 in Page 111
+
+
+clear; clc; close;
+
+// Given data
+// The given polar forms in textbook is represented in rect form
+Z_1 = 17.36482 +%i *98.48078;
+Z_2 = 250;
+Z_3 = 346.4102 +%i *200;
+
+//Calculations
+//The first condition for bridge balance is Z_1*Z_4 = Z_2*Z_3
+mod_Z_4 = (abs(Z_2) *abs(Z_3)/abs(Z_1));
+
+//The second condition for bridge balance requires that sum of the phase angles of opposite arms be equal
+theta_Z_4 = (atan(imag(Z_2),real(Z_2)) +atan(imag(Z_3),real(Z_3)) -atan(imag(Z_1),real(Z_1)))*180/%pi;
+
+printf("The impedence of the unknown arm = %d ohm /_ %d deg\n",mod_Z_4,theta_Z_4);
+printf("Here the magnitude of impedence is 1000 and phase angle is 50 in degrees\n");
+printf("The above value indicates that we are dealing with a capacitive element, possibly consisting of a series combination of a resistor and capacitance");
+
+//Result
+// The impedence of the unknown arm = 1000 ohm /_ -50 deg
+// Here the magnitude of impedence is 1000 and phase angle is 50 in degrees
+// The above value indicates that we are dealing with a capacitive element, possibly consisting of a series combination of a resistor and capacitance
+
+
+
+
diff --git a/174/CH5/EX5.3/example5_3.txt b/174/CH5/EX5.3/example5_3.txt
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+The impedence of the unknown arm = 1000 ohm /_ -50 deg
+Here the magnitude of impedence is 1000 and phase angle is 50 in degrees
+The above value indicates that we are dealing with a capacitive element, possibly consisting of a series combination of a resistor and capacitance