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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Exa2.40
+clc;
+clear;
+close;
+format('v',9)
+// given data
+// First Case:
+r1=1.5/2;// in cm
+// let radius thickness of insulation = r1_t
+r1_t=1.5;// in cm
+r2=r1+r1_t;
+R_desh=500;// in M ohm
+R_desh=R_desh*10^6;// in ohm
+// Second case:
+r1_desh=r1;// in cm (as before)
+// let radius thickness of insulation = r2_t
+r2_t=2.5;// in cm
+r2_desh=r1+r2_t;
+// since Insulation resistance , R_desh= sigma/(2*%pi*l)*log(r2/r1) and
+// R1_desh= sigma/(2*%pi*l)*log(r2_desh/r1_desh)
+// Dividing R1_desh by R1, We get
+// R1_desh/R_desh = log(r2_desh/r1_desh)/log(r2/r1)
+// Let R = R1_desh/R_desh, Now
+R= log(r2_desh/r1_desh)/log(r2/r1);
+R1_desh=R*R_desh;
+disp("New insulation resistance is : "+string(R1_desh*10^-6)+" M ohm");
+
+
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