initial commit / add all books

7 files changed, 96 insertions, 0 deletions

diff --git a/172/CH2/EX2.1/ex1.sce b/172/CH2/EX2.1/ex1.sce
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+//example 1

+//weight of a person

+clear

+clc

+m=1 //kg

+g=9.75 //acc.due to gravity in m/s^2

+F=m*g //weight of 1 kg mass in N

+printf("\n hence,weight of person is F = %.3f N. \n",F)
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diff --git a/172/CH2/EX2.2/ex2.sce b/172/CH2/EX2.2/ex2.sce
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+//example 2

+//average volume and density

+clear

+clc

+Vliq=0.2 //volume of liquid in m^3

+dliq=997 //density of liquid in kg/m^3

+Vstone=0.12 //volume of stone in m^3

+Vsand=0.15 //volume of sand in m^3

+Vair=0.53 //vo;ume of air in m^3

+mliq=Vliq*dliq //mass of liquid in kg

+dstone=2750 //density of stone in kg/m^3

+dsand=1500 //density of sand in kg/m^3

+mstone=Vstone*dstone //volume of stone in m^3

+msand=Vsand*dsand //volume of sand in m^3

+Vtot=1 //total volume in m^3

+dair=1.1 //density of air in kg/m^3

+mair=Vair*dair //mass of air

+mtot=mair+msand+mliq+mstone //total mass in kg

+v=Vtot/mtot //specific volume in  m^3/kg

+d=1/v //overall density in kg/m^3

+printf("\n hence,average specific volume is v=%.6f  m^3/kg. \n",v )

+printf("\n and overall density is d=%.0f kg/m^3. \n",d)
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diff --git a/172/CH2/EX2.3/ex3.sce b/172/CH2/EX2.3/ex3.sce
new file mode 100755
index 000000000..5f17aadba
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+++ b/172/CH2/EX2.3/ex3.sce
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+//example 3

+//calculating the required force

+clear

+clc

+Dcyl=0.1 //cylinder diameter in m

+Drod=0.01 //rod diameter in m

+Acyl=%pi*Dcyl^2/4 //cross sectional area of cylinder in m^2

+Arod=%pi*Drod^2/4 //cross sectional area of rod in m^2

+Pcyl=250000 //inside hydaulic pressure in Pa

+Po=101000 //outside atmospheric pressure in kPa

+g=9.81 //acc. due to gravity in m/s^2

+mp=25 //mass of (rod+piston) in kg

+F=Pcyl*Acyl-Po*(Acyl-Arod)-mp*g //the force that rod can push within the upward direction in N

+printf("\n hence,the force that rod can push within the upward direction is F = %.3f N. \n",F)
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diff --git a/172/CH2/EX2.4/ex4.sce b/172/CH2/EX2.4/ex4.sce
new file mode 100755
index 000000000..6e4c3266e
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+++ b/172/CH2/EX2.4/ex4.sce
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+//example 4

+//Calculating atmospheric pressure 

+clear

+clc

+dm=13534 //density of mercury in kg/m^3

+H=0.750 //height difference between two columns in metres

+g=9.80665 //acc. due to gravity  in m/s^2

+Patm=dm*H*g/1000 //atmospheric pressure in kPa

+printf("\n hence, atmospheric pressure is Patm = %.2f kPa. \n",Patm)
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diff --git a/172/CH2/EX2.5/ex5.sce b/172/CH2/EX2.5/ex5.sce
new file mode 100755
index 000000000..4688e7a4c
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+++ b/172/CH2/EX2.5/ex5.sce
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+//example 5

+//pressure inside vessel

+clear

+clc

+dm=13590 //density of mercury in kg/m^3

+H=0.24 //height difference between two columns in metres

+g=9.80665 //acc. due to gravity  in m/s^2

+dP=dm*H*g //pressure difference in Pa

+Patm=13590*0.750*9.80665 //Atmospheric Pressure in Pa

+Pvessel=dP+Patm //Absolute Pressure inside vessel in Pa

+Pvessel=Pvessel/101325//Absolute Pressure inside vessel in atm

+printf("\n hence, the absolute pressure inside vessel is Pvessel = %.3f atm. \n",Pvessel)
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diff --git a/172/CH2/EX2.6/ex6.sce b/172/CH2/EX2.6/ex6.sce
new file mode 100755
index 000000000..3d74b243c
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+++ b/172/CH2/EX2.6/ex6.sce
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+//example 6

+//calculating pressure

+clear

+clc

+dg=750 //density of gaasoline in kg/m^3

+dR=1206 //density of R-134a in kg/m^3

+H=7.5 //height of storage tank in metres

+g=9.807 //acc. due to gravity in m/s^2

+dP1=dg*g*H/1000 //in kPa

+Ptop1=101 //atmospheric pressure in kPa

+P1=dP1+Ptop1

+disp('hence,pressure at the bottom of storage tank if fluid is gasoline is 156.2 kPa')

+dP2=dR*g*H/1000 //in kPa

+Ptop2=1000 //top surface pressure in kPa

+P2=dP2+Ptop2

+printf("\n hence, pressure at the bottom of storage tank if liquid is R-134a is P2 = %.0f kPa. \n",P2)
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diff --git a/172/CH2/EX2.7/ex7.sce b/172/CH2/EX2.7/ex7.sce
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index 000000000..d3681adae
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+//example 6

+//calculating balancing force

+clear

+clc

+Po=100//Outside atmospheric pressure in kPa

+F1=25 //net force on the smallest piston in kN

+A1=0.01 //cross sectional area of lower piston in m^2

+P1=Po+F1/A1 //fluid pressure in kPa

+d=900 //density of fluid in kg/m^3

+g=9.81 //acc. due to gravity in m/s^2

+H=6 //height of second piston in comparison to first one in m

+P2=P1-d*g*H/1000 //pressure at higher elevation on piston 2 in kPa

+A2=0.05 // cross sectional area of higher piston in m^3

+F2=(P2-Po)*A2 //balancing force on second piston in kN

+printf("\n hence, balancing force on second larger piston is F2 = %.1f N. \n",F2)
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