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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clear;
+clc;
+printf("\nEx2.1\n");
+//page no.-55
+//given
+h=6.60*10^-34;...........//planck's constant in J-s
+m=1.674*10^-27;.........//mass of neutron in Kg
+lambda=10^-10;...........//wavelength in m
+e=1.6*10^-19;.............//charge
+//We know lambda=h/sqrt(2*m*E)
+
+E=(h^2)/(2*m*lambda^2*e)............//energy of neutron in eV
+//to convert into eV divide by e,1.6*10^-19
+
+printf("\nenergy of neutron is 8.12*10^-2 eV\n");