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+//Example 3.7

+clc

+disp("(a)  T = t_p + t_f + t_a")

+tp=(5/470)*10^3

+format(8)

+disp(tp,"Now  t_p(in usec) = nL/R =")

+tf=(50/(470*6*2))*10^3

+format(6)

+disp(tf,"t_f(in usec) = (n/n+1)*L/R*V_CC/V_Y =")

+ta=(1.57*sqrt(5*90*10^-15))*10^6

+disp(ta,"t_a(in usec) = 1.57*sqrt(LC) =")

+t=10.6383+8.865+1.053

+format(8)

+disp(t,"T(in usec) =")

+f=(1/20.5564)*10^3

+disp(f,"Therefore,  f(in kHz) = 1/T =")

+dc=10.6383/20.5564

+format(7)

+disp(dc,"Duty cycle = t_p/T =")

+disp("So duty cycle is 51.75% which is very close to 50% giving an indication that Q ON and OFF times are equal and the output is almost symmetrical square wave.")

+disp("(b)  The collector voltage varies from V_CC-V to V_CC+V_Y")

+v=10/2

+disp(v,"Now  V(in V) = V_CC / n+1 =")

+disp("Therefore,  V_C varies from 10-5 i.e. +5 V to 10+6 = 16 V")

+disp("The base voltage varies from nV to -nV_Y i.e. +5 V to -6 V")

+disp("The emitter current is constant given by,")

+ie=(5/470)*10^3

+format(7)

+disp(ie,"I_E(in mA) = nV/R =")

+ib=(10/(4*470))*10^3

+disp("i_B = V_CC/(n+1)^2 * [n/R - t/L]")

+format(5)

+disp(ib,"So  i_B(max)(in mA) = i_B|t=0 =")

+ib=((10/4)*((1/470)-((10.63*10^-3)/5)))*10^6

+format(6)

+disp(ib,"i_B(t=t_p)(in uA) =")

+disp("i_C = V_CC/(n+1)^2 * [n^2/R + t/L]")

+ic=((10/4)*((1/470)+((10.63*10^-3)/5)))*10^3

+format(7)

+disp(ic,"i_C(t=t_p)(in mA) =")

+i0=(10/940)*10^3

+disp(i0,"I_0 = Peak magnetizing current = n*V_CC / (n+1)*R =")

+disp("(c)  I''_m which is the magnetizing current at the end of one cycle is given by")

+im=(6*sqrt(90/5))

+disp(im,"I''_m(in mA) = V_Y*sqrt(C/L) =")  //answer in textbook is wrong