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authorpriyanka2015-06-24 15:03:17 +0530
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+//practical interpolation
+//example 3.11
+//page 99
+clc;clear;close;
+x=[0.61 0.62 0.63 0.64 0.65 0.66 0.67];
+y=[1.840431 1.858928 1.877610 1.896481 1.915541 1.934792 1.954237];
+h=0.01//interval between values of x
+c=1;
+for i=1:6
+ d1(c)=y(i+1)-y(i);
+ c=c+1;
+end
+c=1;
+for i=1:5
+ d2(c)=d1(i+1)-d1(i);
+ c=c+1
+end
+c=1;
+for i=1:4
+ d3(c)=d2(i+1)-d2(i);
+ c=c+1;
+end
+c=1;
+for i=1:3
+ d4(c)=d3(i+1)-d3(i);
+ c=c+1;
+end
+d=[d1(1) d2(1) d3(1) d4(1)];
+x0=0.638;
+p=(x0-x(4))/h;
+y_x=y(4);
+y_x=y_x+p*(d1(3)+d1(4))/2+p^2*(d2(2))/2;//stirling formula
+printf(' the value at %f by stirling formula is : %f\n\n',x0,y_x);
+y_x=y(3);
+p=(x0-x(3))/h;
+y_x=y_x+p*d1(3)+p*(p-1)*(d2(2)/2);
+printf(' the value at %f by bessels formula is : %f\n\n',x0,y_x);