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authorpriyanka2015-06-24 15:03:17 +0530
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+//example 7
+// power generation by steam turbine
+clear
+clc
+P1= 2 //initial pressure of steam in MPa
+T1= 400 //initial temp. of steam in °C
+V1= 50 //initial velocity of steam in m/s
+z1= 10 //height of inlet in metres
+h1=3248.4 //initial specific enthalpy of air in kJ/kg
+P2= 15 //final pressure of air in kPa
+V2= 180 //final velocity of air in m/s
+z2= 6 //exit height in m
+x2=0.9 //quality of steam after exit
+disp('At turbine exit,we obviously have liquid vapour mixture at 15 kPa.')
+hf=225.94 //in kJ/kg
+hfg=2372.3 //in kJ/kg
+h2=hf+x2*hfg //final specific enthalpy of mixture in kJ/kg
+dh=h2-h1 // change in enthalpy of steam in kJ/kg
+dke=(V2^2-V1^2)/2000 //change in kinetic energy of steam in kJ/kg
+g=9.8 //acc. due to gravity in m/s^2
+dpe=g*(z2-z1)/1000//change in potential energy of steam in kJ/kg
+wout=-((h2-h1)+(V2^2-V1^2)/2000+g*(z2-z1)/1000) //work done per unit mass of the steam flowing through the turbine in kJ/kg
+m=5000/wout //mass flow rate of steam in kg/s
+printf("\n The value of dh is = %.2f kJ/kg. \n",dh);
+printf("\n The value of dke is = %.2f kJ/kg. \n",dke);
+printf("\n The value of dpe is = %.2f kJ/kg. \n",dpe);
+printf("\n The work done per unit mass of the steam flowing through the turbine is = %.2f kJ/kg. \n",wout);
+printf("\n The mass flow rate of the steam is = %.2f kg/s. \n",m); \ No newline at end of file