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authorpriyanka2015-06-24 15:03:17 +0530
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+//ques12
+//Using Generalized Charts to Determine Pressure
+clc
+//(a)
+R=0.5956;//Gas constant for a given substance in psia.ft^3/lbm.R
+Pcr=3200;//Critical Pressure in psia
+Tcr=1164.8;//Critical Temp in R
+v=0.51431;//specific volume in ft^3/lbm
+T=600;//Temperature in F
+//so
+P=1000;//Pressure in psia from Table A-6E
+printf('\n(a) Pressure at a specified state = %.0f psia',P);
+//(b)
+T=1060;//Temperature in F
+P=R*T/v;//Pressure in psia
+printf('\n(b)Pressure of the steam under specified condition = %.0f psia',P);
+//(c)using generalised compressibility chart
+Vr=v*Pcr/(R*Tcr/Pcr);//reduced volume
+Tr=T/Tcr;//reduced temperature
+//so
+Pr=0.33;//from compressibility chart
+P=Pr*Pcr;//final Pressure in psia
+printf('\n(c) Pressure(using generalised compressibility chart) = %.0f psia ',P);