initial commit / add all books

14 files changed, 167 insertions, 0 deletions

diff --git a/167/CH2/EX2.1/ex1.sce b/167/CH2/EX2.1/ex1.sce
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+// example 1

+// general energy analysis

+clear

+clc

+d=0.75 //density of gasoline in kg/l

+v=5 //average consumption of gasoline by the car in litres/day

+h=44000 //heating value of gasoline in kJ/kg

+disp('daily consumption of fuel = c = d*v ')

+c=d*v //average consumption of gasoline in kg/day

+e=c*h //daily energy requirement of car in kJ/day

+E=0.1*6.73*10^10 //energy released by complete fussion of 0.1 kg of uranium in kJ

+x=E/e //no. of days for which E amount of energy can meet the energy requirements of car

+printf("\n Hence, the car will require refilling after = %.0f years. \n",x/365);
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diff --git a/167/CH2/EX2.10/ex10.sce b/167/CH2/EX2.10/ex10.sce
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+//example 10

+// cooling of hot fluid in tank

+clear

+clc

+disp('suppose that there is no change in kinetic and potential energy ')

+u1=800 //initial internal energy in 800kJ

+win=100 //work done by paddle on system in kJ

+qout=500 //loss of energy from fluid

+disp('applying first law of thermodynamics ')

+u2=u1-qout+win //final internal energy in kJ

+printf("\n Hence,final internal energy of the fluid is = %.1f kJ. \n",u2);
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diff --git a/167/CH2/EX2.11/ex11.sce b/167/CH2/EX2.11/ex11.sce
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+//example 11

+// acceleration of air by fan

+clear

+clc

+v=8 //discharge rate of air in m/s

+m=0.25 //mass flow rate in kg/s

+p=m*v^2/2 //actual power consumed in W

+P=20 //claimed power in W

+disp('since,two  powers are not equal,this claim is not reasonable ')
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diff --git a/167/CH2/EX2.12/ex12.sce b/167/CH2/EX2.12/ex12.sce
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+//example 12

+//heating effect of a fan

+clear

+clc

+t1=25 //initial temperature of room in C

+p=200 //power consumption of fan in watts

+a=30 //exposed surface area in m^2

+u=6 //in w/m^2

+t2=p/(u*a)+t1 //final temp. of room in C

+printf("\n Hence, the indoor air temperature when steady operating conditions are established is = %.1f C. \n",t2);
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diff --git a/167/CH2/EX2.13/ex13.sce b/167/CH2/EX2.13/ex13.sce
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+//example 13

+// annual lighting cost of a classroom

+clear

+clc

+p=80 //power consumed by fluoroscent lamp in watt

+n=30 //no. of lamps used

+P=p*n/1000 //lighting power in kW

+t=250*12 //operating hours in a year

+E=P*t //lighting energy/year

+c=E*0.07 //cost of lighting  a classroom for a year in dollars

+printf("\n Hence,annual energy cost of lighting for the classroom is = %.0f $/year. \n",c);
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diff --git a/167/CH2/EX2.15/ex15.sce b/167/CH2/EX2.15/ex15.sce
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+//example 15

+//cost of cooking with electric and gas charges

+clear

+clc

+e1=73 //efficiency of open burner for electric units

+e2=38 //efficiency of open burner for gas units

+E1=2 //Electrical energy input in 2kW

+q1=E1*e1/100 //actually utilised electrical energy in kWh

+c=0.09/0.73 //cost of utilised energy per kWh

+q2=q1/(e2/100) //energy input to a gas burner in kW

+c=(0.55/29.3)/(e2/100) //cost of utilised energy of gas burner

+printf("\n Hence,rate of energy consumption by the burner is = %.2f kW. \n",q2);

+printf("\n The cost of utilised energy is = $ %.3f /kWh. \n",c);
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diff --git a/167/CH2/EX2.16/ex16.sce b/167/CH2/EX2.16/ex16.sce
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+// example 16

+// performance of hydraulic turbine generator

+clear

+clc

+h=50 //depth of lake in metres

+m=5000 // mass flow rate of water in kg/s

+g=9.81 //acc. due to gravity in m/s^2

+disp('change in mechanical energy= ')

+e=g*h/1000 //change in mech. energy in kJ/kg

+E1=e*m //Rate at which mechanical energy is supplied to the turbine in kW

+E2=1862 //electric power generated in kW

+n1=E2/E1 //overall efficiency

+n2=0.95 //efficiency of generator

+n3=n1/n2 //efficiency of turbine

+W=n3*E1 //shaft power output in kW

+printf("\n Hence,overall efficiency of turbine generator is = %.2f. \n",n1);

+printf("\n The mechanical efficiency of the turbine is = %.2f. \n",n3);

+printf("\n The shaft power supplied by the turbine to the generator is =%.0f kW.\n",W)
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diff --git a/167/CH2/EX2.17/ex17.sce b/167/CH2/EX2.17/ex17.sce
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+//example 17

+//Cost Savings Associated with High-Efficiency motors

+clear

+clc

+n1=89 //efficiency of first motor

+n2=93.2 //efficiency of second motor

+c=0.08 //cost of electricity in $/kWh

+p=60*0.7457 //rated power in kW

+h=3500 //operating hours per year

+e=p*h*(1/(n1/100)-1/(n2/100)) //energy savings

+s=e*c //cost savings

+t=640/s //simple payback period in year

+printf("\n Hence,the amount of energy saved is = %.0f kWh/year. \n",e);

+printf("\n The money saved is =%.0f $/year. \n",s);

+printf("\n The payback period is=%.2f years.\n",t);
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diff --git a/167/CH2/EX2.18/ex18.sce b/167/CH2/EX2.18/ex18.sce
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+//example 18

+//reducing air pollution by geothermal heating

+clear

+clc

+s=18*10^6 //quantity of natural gas that will be saved per year in therms

+nn=0.0047 //quantity of NOx in kg/therm

+nc=6.4 //quantity of CO2 in kg/therm

+sn=nn*s //NOx savings per year in kg/year

+sc=nc*s //CO2 savings per year in kg/year

+printf("\n Hence,geothermal system will save  %.1f *10^4 kg NOx/year. \n",sn/10^4);

+printf("\n and = %.1f *10^8 kg CO2/year. \n",sc/10^8);
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diff --git a/167/CH2/EX2.19/ex19.sce b/167/CH2/EX2.19/ex19.sce
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+// example 19

+// heat transfer from a person

+clear

+clc

+T1=20 //room temperature in celsius

+T2=29 //body temperature of person in celsius

+a=1.6 //exposed surface area in m^2

+h=6 //convection heat transfer coefficient in W/m^2*C

+Qc=h*a*(T2-T1) //heat loss due convection in W

+Qr=0.95*5.67*10^-8*a*((T2+273)^4-(T1+273)^4) //heat loss due to radiation in W

+Q=Qc+Qr //net heat loss from the person in W

+printf("\n Hence,the total rate of heat transfer is =%.1f W. \n",Q) 
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diff --git a/167/CH2/EX2.2/ex2.sce b/167/CH2/EX2.2/ex2.sce
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+//example 2

+//analysis of wind energy

+clear

+clc

+v=8.5 //velocity of wind in m/s

+e=v^2/2 //wind energy per unit mass of air in j/kg

+m=10 //mass of wind to be considered in kg

+E=m*e //energy in joules of wind of mass m 

+mf=1154 //mass flow rate in kg/s

+Ef=mf*e //wind energy in W for a mass flow rate of mf

+printf("\n Hence,wind energy per unit mass is = %.1f J/kg. \n",e);

+printf("\n The wind energy for a mass of 10 kg is = %.0f J. \n",E);

+printf("\n The wind energy for flow rate of 1154 kg/s is = %.1f kW. \n",Ef/1000);
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diff --git a/167/CH2/EX2.7/ex7.sce b/167/CH2/EX2.7/ex7.sce
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+// example 7

+// Power Transmission by the Shaft of a Car

+clear

+clc

+t=200 //torque applied in N.m

+rpm=4000 //revolutions per minute of shaft

+n=rpm/60 //revolutions per second of shaft 

+w=2*%pi*n*t // shaft power in watts

+printf("\n Hence,power transmitted by the shaft of car is = %.1f kW. \n",w/1000);
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diff --git a/167/CH2/EX2.8/ex8.sce b/167/CH2/EX2.8/ex8.sce
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index 000000000..4d1a72ca2
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+// example 8

+// Power Needs of a Car to Climb a Hill

+clear

+clc

+m=1200 //mass of car in kg

+v1=90 //velocity of car in km/h

+v2=90*5/18 //velocity of car in m/s

+x=30 //slope of hill in degrees

+g=9.8 //acc. due to gravity in m/s^2

+w=m*g*v2*sin(%pi*30/180) //additional power to be delivered by engine in watts

+printf("\n Hence,additional power to be delivered by engine is = %.0f kW. \n",w/1000);
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diff --git a/167/CH2/EX2.9/ex9.sce b/167/CH2/EX2.9/ex9.sce
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+// example 9

+// power needs of a car to accelerate 

+clear

+clc

+m=900 //mass ofcar in kg

+v1=0 //initial velocity of car

+v2=80*5/18 //final velocity of car in m/s

+t=20 //time in which the car has to reach its desired speed in seconds

+w=m*(v2^2-v1^2)/2 //work required to accomplish this task in joules

+p=w/t // power required in watts

+printf("\n Hence,power required to accelerate is = %.1f kW. \n",p/1000);
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