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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /167/CH15/EX15.6 | |
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Diffstat (limited to '167/CH15/EX15.6')
| -rwxr-xr-x | 167/CH15/EX15.6/ex6.sce | 17 |
1 files changed, 17 insertions, 0 deletions
diff --git a/167/CH15/EX15.6/ex6.sce b/167/CH15/EX15.6/ex6.sce new file mode 100755 index 000000000..343de4863 --- /dev/null +++ b/167/CH15/EX15.6/ex6.sce @@ -0,0 +1,17 @@ +//example 6
+//First-Law Analysis of Steady-Flow Combustion
+clear
+clc
+mair=7.5*4.76*29 //mass of air in kg
+mfuel=3*12+4*2 //mass of fuel in kg
+AF=mair/mfuel //air fuel ratio
+Mfuel=0.05 //Mass flow rate of fuel in kg/min
+Mair=AF*Mfuel //mass flow rate of air in kg/min
+qout=1*(-118910)+7.5*(8150-8682)+28.2*(0+8141-8669)-2.7*(-393520+71078 -9364)-0.3*(-110530+47517-8669)-4*(-241820+57999-9904)-2.65*(0+49292-8682)-28.2*(0+47073-8669) //in kJ/kmol C3H8
+disp('This heat is transferred from the combustion chamber for each kmol (44kg) of propane.therefore qout = qout/44 kJ/kg')
+qout=qout/44 //in kJ/kg propane
+M=0.05 //mass flow rate of liquid propane in kg/min
+Qout=M*qout //rate of heat transfer in kJ/min
+Qout=Qout/60 //rate of heat reansfer in kW
+printf("\n Hence, the mass flow rate of air is = %.2f kg/min. \n",Mair);
+printf("\n and the rate of heat transfer from combustion chamber is = %.2f kW. \n",Qout);
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