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authorpriyanka2015-06-24 15:03:17 +0530
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+clc
+clear
+
+//INPUT DATA
+cp=0.23;//specific heat at constant pressure in kj/kg-K
+a=1.18;//density of air in gm/lit
+J=4.2*10^7;//mechanical equivalent of heat in ergs/cal
+t=300;//temperature of air in kelvin
+p=73*13.6*981;//pressure of air in dynes
+//cp-cv=(r/J)=pv/(tj)
+
+//CALCULATON
+cv=cp-(p*1000/(a*t*J));//specific heat at constant volume in calories
+
+//OUTPUT
+mprintf('the specific heat at constant volume is %3.5f calories',cv)