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10 files changed, 129 insertions, 0 deletions

diff --git a/1553/CH23/EX23.1/23Ex1.sce b/1553/CH23/EX23.1/23Ex1.sce
new file mode 100644
index 000000000..e18d40e28
--- /dev/null
+++ b/1553/CH23/EX23.1/23Ex1.sce
@@ -0,0 +1,24 @@
+// Chapter 23 Ex1

+

+clc;

+clear;

+close;

+

+//(i)

+

+n1=27; n2=3;

+ans1=log(n1)/log(n2);

+mprintf("log 27 to the base 3 is %d",ans1);

+

+//(ii)

+

+n3=(1/343); n4=7;

+ans2=log(n3)/log(n4);

+mprintf("\nlog (1/343) to the base 7 is %d",ans2);

+

+//(iii)

+

+n5=0.01; n6=100;

+ans3=log(n5)/log(n6);

+mprintf("\nlog 0.01 to the base 100 is %.0f",ans3);

+

diff --git a/1553/CH23/EX23.10/23Ex10.sce b/1553/CH23/EX23.10/23Ex10.sce
new file mode 100644
index 000000000..b4da36ae5
--- /dev/null
+++ b/1553/CH23/EX23.10/23Ex10.sce
@@ -0,0 +1,10 @@
+// Chapter 23 Ex. 10

+

+clc;

+clear;

+close;

+//given log2 =0.30103

+//consider x=log2

+x=0.30103;

+ans=56*x;

+mprintf("The number of digits are %.0f",ans);
\ No newline at end of file
diff --git a/1553/CH23/EX23.2/23Ex2.sce b/1553/CH23/EX23.2/23Ex2.sce
new file mode 100644
index 000000000..fdb82aab3
--- /dev/null
+++ b/1553/CH23/EX23.2/23Ex2.sce
@@ -0,0 +1,21 @@
+//chapter 23 Ex 2

+

+clc;

+clear;

+close;

+

+//(i)

+n1=1; n2=7;

+ans1=log(n1)/log(n2);

+mprintf("log %d to base %d is %d",n1,n2,ans1);

+

+//(ii)

+n3=34; n4=34;

+ans2=log(n3)/log(n4);

+mprintf("\n log %d to base %d is %d",n3,n4,ans2);

+

+//(iii)

+base=36; n5=4; n6=6;

+power=log(n5)/log(n6);

+ans3=base^power;

+mprintf("\n The ans is %.0f",ans3);

diff --git a/1553/CH23/EX23.3/23Ex3.sce b/1553/CH23/EX23.3/23Ex3.sce
new file mode 100644
index 000000000..47e4495d2
--- /dev/null
+++ b/1553/CH23/EX23.3/23Ex3.sce
@@ -0,0 +1,8 @@
+// Chapter 23 Ex3

+

+clc;

+clear;

+close;

+ans=(10/3); n1=sqrt(8);

+x=(n1)^ans;  // derived from equation log x to the base n1=ans.

+mprintf("The value of x is %.0f",x);

diff --git a/1553/CH23/EX23.4/23Ex4.sce b/1553/CH23/EX23.4/23Ex4.sce
new file mode 100644
index 000000000..c3dfb8d95
--- /dev/null
+++ b/1553/CH23/EX23.4/23Ex4.sce
@@ -0,0 +1,14 @@
+//chapter 23 Ex 4

+

+clc;

+clear;

+close;

+//(i)

+n1=3; n2=5; n3=25; n4=27;

+ans1=(log(n1)/log(n2))*(log(n3)/log(n4));

+mprintf("The answer is %.2f",ans1);

+

+//(ii)

+n5=27; n6=9; n7=9; n8=27;

+ans2=(log(n5)/log(n6))-(log(n7)/log(n8));

+mprintf("\nThe answer is %.2f",ans2);

diff --git a/1553/CH23/EX23.5/23Ex5.sce b/1553/CH23/EX23.5/23Ex5.sce
new file mode 100644
index 000000000..91117154b
--- /dev/null
+++ b/1553/CH23/EX23.5/23Ex5.sce
@@ -0,0 +1,8 @@
+// Chapter 23 Ex5

+

+clc;

+clear;

+close;

+n1=75; n2=16; n3=5; n4=9; n5=32; n6=243;

+ans=(log(n1/n2)-2*log(n3/n4)+log(n5/n6));

+mprintf("The answer of the equation is %.2f",ans);
\ No newline at end of file
diff --git a/1553/CH23/EX23.6/23Ex6.sce b/1553/CH23/EX23.6/23Ex6.sce
new file mode 100644
index 000000000..3c98b5b76
--- /dev/null
+++ b/1553/CH23/EX23.6/23Ex6.sce
@@ -0,0 +1,14 @@
+// Chapter 23 Ex6

+

+clc;

+clear;

+close;

+n1=3;

+//x=poly(0,'x');

+for x=1:.5:10

+    if log10((4*x+1)/(x+1))==(1-(log10(n1)))

+        

+        break;

+end

+end

+mprintf("The value of x is %.2f",x);

diff --git a/1553/CH23/EX23.7/23Ex7.sce b/1553/CH23/EX23.7/23Ex7.sce
new file mode 100644
index 000000000..e2a2323f4
--- /dev/null
+++ b/1553/CH23/EX23.7/23Ex7.sce
@@ -0,0 +1,8 @@
+// Chapter 23 Ex7

+

+clc;

+clear;

+close;

+x=1; y=2; z=3;

+ans=(1/(log((x)*(y)*(z))/log((x)*(y))))+(1/(log((x)*(y)*(z))/log((z)*(y))))+(1/(log((x)*(y)*(z))/log((x)*(z))));

+mprintf("The answer is %d",ans);
\ No newline at end of file
diff --git a/1553/CH23/EX23.8/23Ex8.sce b/1553/CH23/EX23.8/23Ex8.sce
new file mode 100644
index 000000000..fb5120cb5
--- /dev/null
+++ b/1553/CH23/EX23.8/23Ex8.sce
@@ -0,0 +1,8 @@
+//chapter 23 Ex 8

+

+clc;

+clear;

+close;

+n1=50; n2=10;

+ans1=log10(n1)

+mprintf("The value of log %d to base %d is %.3f",n1,n2,ans1);

diff --git a/1553/CH23/EX23.9/23Ex9.sce b/1553/CH23/EX23.9/23Ex9.sce
new file mode 100644
index 000000000..8abfc9d72
--- /dev/null
+++ b/1553/CH23/EX23.9/23Ex9.sce
@@ -0,0 +1,14 @@
+//chapter 23 Ex 9

+

+clc;

+clear;

+close;

+//(i)

+n1=25

+ans1=log10(n1);

+mprintf("The value of log %d is %.3f",n1,ans1);

+

+//(ii)

+n2=4.5

+ans2=log10(n2);

+mprintf("The value of log %d is %.3f",n2,ans2);