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+// Scilab code Ex2.9: Pg 52-53 (2008)

+clc; clear;

+R1 = 3;                // Resisance, ohms

+R2 = 2;                // Resistance, ohms

+R3 = 10;               // Resistance, ohms

+E1 = 10;               // E.m.f, V

+E2 = 4;                 // E.m.f, V

+// Applying Kirchhoff ’ s Current Law(the sum of the currents arriving at a junction is equal to the sum of the currents leaving that junction) 

+A = [3 -2; 13 10];

+B = [6; 10];

+X = inv(A)*B;

+I1 = X(1,:);                     // Electric current through branch FA, A

+I2 = X(2,:);                     // Eleactric current through branch EB, A

+I3 = ( I1 + I2 );                // Electric current through branch CD, A

+V_CD = R3*I3;                    // P.d.across R3 resistor, V

+printf("\nThe current through branch FA = %6.3f A", I1);

+printf("\nThe current through branch EB = %5.3f A", I2);

+printf("\nThe current through branch CD = %5.3f A", I3);

+printf("\np.d.across %2d resistor = %4.2f V", R3, V_CD);

+

+// Result

+// The current through branch FA = 1.429 A

+// The current through branch FA = -0.857 A

+// The current through branch FA = 0.571 A

+// p.d.across %2d resistor = 5.71 V