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authorpriyanka2015-06-24 15:03:17 +0530
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+//example-5.1
+//page no-136
+//given
+//wavelength of X-rays beams of light
+lambda=0.824*10^-10 //m
+//glancing angle of the incident light
+theta1=(8+35/60)*(%pi)/180 //radians
+n1=1
+//to find theta3 i.e at
+n3=3
+//as we know that
+//2*d*sin(theta)=n*lambda
+//so for n1 and n3 we get in the same way and solving together we get
+theta3=asin(3*sin(theta1))
+//so
+d=lambda/2/sin(theta1)
+printf ("the galncing angle for thethird order diffraction is and interplanar spacing of the crystal is 2.761 A")