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authorpriyanka2015-06-24 15:03:17 +0530
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+//example-18.5
+//page no-548
+//given
+//resistance of wire at 70 degree celcius is 57.2 ohm and at 25 degrees celcius 50 ohm
+R25=50 //ohm
+R70=57.2 //ohm
+T1=25 //degree C
+T2=70 //degree C\
+//as we know that
+//Rt=R0*(1+t*alpha)
+//putting above values in the above given equation we get
+//R25=R0*(1+25*alpha) -------(1)
+//R70=R0*(1+70*alpha) --------(2)
+//applying R70/R25
+//we get
+//R70/R25=(1+70*alpha)/(1+25*alpha)
+//solving for alpha we get equation as follows
+alpha=(R70-R25)/(T2*R25-T1*R70) //K^-1
+printf ("the temperature coefficient of resistance is %f K^-1",alpha)