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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter 10, Problem 9, figure 10.19
+clc;
+tc = 500e-6; // in s/cm
+Vc = 5; // in V/cm
+w = 4; // in cm ( width of one complete cycle )
+h = 5; // in cm ( peak-to-peak height of the display )
+//calculation:
+T = w*tc
+f = 1/T
+ptpv = h*Vc
+Amp = ptpv/2
+Vrms = Amp/(2^0.5)
+printf("\n\n (a)Frequency, f = %.0f Hz",f)
+printf("\n\n (b)the peak-to-peak voltage = %.0f V",ptpv)
+printf("\n\n (c)Amplitude = %.1f V",Amp)
+printf("\n\n (d)r.m.s voltage = %.2f V",Vrms)