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+//Chapter 10, Problem 4, figure 10.10

+clc;

+R=500;              //load resistance

+V=10;               //supply voltage

+ra=50;              //ammeter resistance

+Ie=V/R;             //calculating expected current

+Ia=V/(R+ra);        //calculating actual current

+P=Ia^2*ra;          //calculating power dissipated in the ammeter

+Pl=Ia^2*R;          //calculating power dissipated in load resistor

+printf("(a) Expected ammeter reading = %f mA\n\n\n",Ie*1000);

+printf("(b) Actual ammeter reading = %f mA\n\n\n",Ia*1000);

+printf("(c) Power dissipated in the ammeter = %f mW\n\n\n",P*1000);

+printf("(d) Power dissipated in the load resistor = %f mW\n\n\n",Pl*1000);