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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter 10, Problem 22
+clc
+I=2.5e-3 //current in amperes
+R=5000 //resistance in ohm
+e1=0.4 //error tolerance
+e2=0.5 //error tolerance
+V=I*R
+emax=e1+e2
+V1=(emax/100)*V
+printf("V = %.1f V\n accuracy = %.2f V\n",V,V1)