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+//Network Theorem 2

+//pg no 3.12

+//example 3.11

+//when 5 A source is acting alone

+disp("-V1+4I=0");//equation 1

+disp("Applying KCL to node 1,");

+disp("1.25V1-4I=5");//equation 2

+A=[-1 4;1.25 -4];//solving equation in matrix form

+B=[0 5]'

+X=inv(A)*B;

+disp(X);

+disp("V1 = 20 V");

+//when the 20 V source is acting alone

+disp("from the figure,");

+disp("V2-3I=0");//equation 1

+disp("Applying KVL to the mesh,");

+disp("I=-20");//equation 2

+A=[1 -3;0 1];//solving equation in matrix form

+B=[0 -20]'

+X=inv(A)*B;

+disp(X);

+disp("V2 = -60 V");

+a=20;

+b=-60;

+x=a+b;

+mprintf("\nBy superposition theorem, \n V = V1+V2 = %.f V ",x);