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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Network Theorem 1
+//page no-2.34
+//example2.30
+disp("Applying KCL to node 1:");
+disp("8*V1-V2 = 50");....//equation 1
+disp("Applying KCL to node 2:");
+disp("-2*V1+11*V2 = -500");...//equation 2
+disp("Solving equations 1 and 2");...//solving equations in matrix form
+A=[8 -1;-2 17];
+B=[50 -500]'
+X=inv(A)*B;
+disp(X);
+disp("V1= 2.61 V");
+disp("V2=-29.1 V");
+x=2.61;
+y=-29.1;
+I1=-x/2;
+I2=(x-y)/10;//current through 10 Ohm resistor
+I3=(y+50)/2;//50 volts is the supply to the circuit
+mprintf("\nI1= %.2f A \nI2= %.2f A \nI3= %.2f A",I1,I2,I3);
+