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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Network Theorem 1
+//page no-2.30
+//example2.26
+disp("Applying KCL to node 1:");
+disp("5*V1-2*V2 = -24");....//equation 1
+disp("Applying KCL to node 2:");
+disp("10*V1-31*V2+6*V3 = 300");...//equation 2
+disp("Applying KCL to node 3:");
+disp("-4*V2 +9*V3 = 160");...//equation 3
+disp("Solving equations 1,2 and 3");...//solving equations in matrix form
+A=[5 -2 0;10 -31 6;0 -4 9];
+B=[-24 300 160]'
+X=inv(A)*B;
+disp(X);
+disp("V1= -8.77 V");
+disp("V2= -9.92 V");
+disp("V3= 13.37 V");
+x=13.37;
+y=-9.92;
+z=(x-y)/5;
+printf("\ncurrent through the 5 ohm resistor = V3-V2/5 = %.2f A",z);