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+//Network Theorem 1

+//page no-2.26

+//example2.20

+disp("writing equation for supermesh,");

+disp("I1-I3=7");....//equation 1

+disp("Applying Kvl to the outer path of the supermesh:");

+disp("-I1+4*I2-4*I3 = -7");....//equation 2

+disp("Applying Kvl to mesh 2:");

+disp("I1-6*I2+3*I3 = 0");...//equation 3

+disp("Solving equations 1 ,2 and 3");...//solving equations in matrix form

+A=[1 0 -1;-1 4 -4;1 -6 3];

+B=[7 -7 0]'

+X=inv(A)*B;

+disp(X);

+disp("I1=9 A");

+disp("I2=-2.5 A");

+disp("I3=-2 A");

+x=2.5;

+y=2;

+z=x-y;

+mprintf("\nCurrent through the 3-Ohm resistor = I2-I3 =%.1f A",z);