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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Basic Circuit Concepts
+//page no-1.13
+//example1.7
+I1=5/2;
+printf("I1=2/5= %2f Ampere", I1)
+I2=2;
+printf("\nI2=4/8= %2f Ampere", I2)
+disp("Potential difference VAB = VA - VB");
+disp("Writing KVL equations for path A to B") //Writing KVL equations for path A to B
+disp("VA - 2*I1 + 8 - 5*I2 - VB = 0");
+disp("VA - VB = (2*2.5) - 8 5 + (5*2)");
+VAB=(2*2.5)-8+(5*2)
+printf("VAB = %.2f Volt", VAB); \ No newline at end of file