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authorpriyanka2015-06-24 15:03:17 +0530
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+//chapter 2
+//example 2.3
+//page 34
+clear;
+clc ;
+//given
+If=50;//in mA
+Rl=100;//in ohm
+Ef=1.1;//in volts at point Q plotted at If=50mA
+//finding voltage across Rl(Ef)
+deltaIf=0.05;//in Ampere(when If changes from 50-0 mA)
+deltaEf=deltaIf*Rl;//in volts
+newEf=Ef+deltaEf;
+Es=6.1;//read from point A on load line after joining A and Q
+printf('New value of Ef is %.1f V .Therefore Es(supply voltage) is %.1f V',newEf,Es)
+
+