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authorpriyanka2015-06-24 15:03:17 +0530
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+// Example 4.8 page no-208
+clear
+clc
+
+alfa=0.98
+Ie=-2 //in mA IE is negative because it is NPN transistor
+Ic=-alfa*Ie
+Ib=(1-alfa)*(-Ie)
+vbe=0.6 //V
+vcc=12 //V
+re=100 //ohm
+r2= 20000 //ohm
+r1=3.3 //k-Ohm
+vbn=vbe-(Ie*re*10^-3)
+printf("\nIc = %.2f mA\nIb = %.0f micro A\nV_BN =%.1f V",Ic,Ib*1000,vbn)
+Ir2=vbn*10^3/r2
+Ir1=Ir2+Ib
+printf("\nIR1 = %.0f micro A\nIR2 = %.0f micro A\nIrc = %.2f mA",Ir1*1000,Ir2*1000,Ir1+Ic)
+vr1=vcc-((Ir1+Ic)*r1)-vbn
+R1=vr1/Ir1
+printf("\nR1=%d K-Ohm",ceil(R1))