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authorpriyanka2015-06-24 15:03:17 +0530
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+// Example 2.16 page no-71
+clear
+clc
+
+A = 9.64 * 10^14
+EG = 0.25 //eV
+n1 = 6.25*10^26///cm^3
+na=3*10^14
+nd=2*10^14
+n=-(10^14)+(sqrt(10^28+4*6.25*10^26))
+n=n/2
+printf("\nn=%.1f*10^12 electrons/cm^3\np=%.2f*10^14 holes/cm^3\nAs p> n, this is p-type semiconductor.",n/10^12,(n+10^14)/10^14)