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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /149/CH4/EX4.10/ques10.sce | |
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initial commit / add all books
Diffstat (limited to '149/CH4/EX4.10/ques10.sce')
-rwxr-xr-x | 149/CH4/EX4.10/ques10.sce | 37 |
1 files changed, 37 insertions, 0 deletions
diff --git a/149/CH4/EX4.10/ques10.sce b/149/CH4/EX4.10/ques10.sce new file mode 100755 index 000000000..604fbf59d --- /dev/null +++ b/149/CH4/EX4.10/ques10.sce @@ -0,0 +1,37 @@ +clc
+disp(' y^(1/m)+y^-(1/m)=2x ');
+disp(' OR y^(2/m)-2xy^(1/m)+1');
+disp('OR y=[x+(x^2-1)]^m and y=[x-(x^2-1)]^m ');
+
+syms x m
+disp('For y=[x+(x^2-1)]^m ');
+ y=(x+(x^2-1))^m
+disp('we have to prove (x^2-1)y(n+2)+(2n+1)xy(n+1)+(n^2-m^2)yn ') ;
+//n=input('Enter the order of differentiation ");
+disp('calculating yn for various values of n');
+for n=1:4
+
+ //yn=diff(F,x,n)
+ F=(x^2-1)*diff(y,x,n+2)+(2*n+1)*x*diff(y,x,n+1)+(n^2-m^2)*diff(y,x,n);
+ disp(n);
+ disp('the expression for yn is ');
+ disp(F);
+ disp('Which is equal to 0 ');
+
+end
+disp('For y=[x-(x^2-1)]^m ');
+ y=(x-(x^2-1))^m
+disp('we have to prove (x^2-1)y(n+2)+(2n+1)xy(n+1)+(n^2-m^2)yn ') ;
+//n=input('Enter the order of differentiation ");
+disp('calculating yn for various values of n');
+for n=1:4
+
+ //yn=diff(F,x,n)
+ F=(x^2-1)*diff(y,x,n+2)+(2*n+1)*x*diff(y,x,n+1)+(n^2-m^2)*diff(y,x,n);
+ disp(n);
+ disp('the expression for yn is ');
+ disp(F);
+ disp('Which is equal to 0 ');
+
+end
+disp('Hence proved');
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