updated the code

2 files changed, 82 insertions, 82 deletions

diff --git a/149/CH23/EX23.2/ex2.sce b/149/CH23/EX23.2/ex2.sce
index a911a74f7..313e9064a 100755
--- a/149/CH23/EX23.2/ex2.sce
+++ b/149/CH23/EX23.2/ex2.sce
@@ -1,39 +1,39 @@
-clc

-disp('the first row of A represents the mid values of weekly earnings having interval of 2 in each class=x')

-A(1,:)=[11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41]

-disp('the second row denotes the no. of employees or in other words frequency=f')

-A(2,:)=[3 6 10 15 24 42 75 90 79 55 36 26 19 13 9 7]

-disp('third row denotes f*x')

-for i=1:16

-  A(3,i)=A(1,i)*A(2,i);

-end

-disp('fourth row denotes u=(x-25)/2')

-for i=1:16

-  A(4,i)=(A(1,i)-25)/2

-end

-disp('fifth row denotes f*x')

-for i=1:16

-  A(5,i)=A(4,i)*A(2,i);

-end

-A

-b=0;

-disp('sum of all elements of third row=')

-for i=1:16

-  b+=A(3,i)

-end

-disp(b)

-f=0;

-disp('sum of all elements of second row=')

-for i=1:16

-  f+=A(2,i)

-end

-disp(f)

-disp('mean=')

-b/f

-d=0;

-disp('sum of all elements of fifth row=')

-for i=1:16

-  d+=A(5,i)

-end

-disp('mean  by step deviation method=')

+clc
+disp('the first row of A represents the mid values of weekly earnings having interval of 2 in each class=x')
+A(1,:)=[11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41]
+disp('the second row denotes the no. of employees or in other words frequency=f')
+A(2,:)=[3 6 10 15 24 42 75 90 79 55 36 26 19 13 9 7]
+disp('third row denotes f*x')
+for i=1:16
+  A(3,i)=A(1,i)*A(2,i);
+end
+disp('fourth row denotes u=(x-25)/2')
+for i=1:16
+  A(4,i)=(A(1,i)-25)/2
+end
+disp('fifth row denotes f*x')
+for i=1:16
+  A(5,i)=A(4,i)*A(2,i);
+end
+A
+b=0;
+disp('sum of all elements of third row=')
+for i=1:16
+  b=A(3,i)
+end
+disp(b)
+f=0;
+disp('sum of all elements of second row=')
+for i=1:16
+  f=f+A(2,i)
+end
+disp(f)
+disp('mean=')
+b/f
+d=0;
+disp('sum of all elements of fifth row=')
+for i=1:16
+  d=d+A(5,i)
+end
+disp('mean  by step deviation method=')
 25+(2*d/f)
\ No newline at end of file
diff --git a/149/CH23/EX23.8/ex8.sce b/149/CH23/EX23.8/ex8.sce
index 201157e53..219a662d9 100755
--- a/149/CH23/EX23.8/ex8.sce
+++ b/149/CH23/EX23.8/ex8.sce
@@ -1,45 +1,45 @@
-clc

-disp('the first row of A represents the mid values of wage classes having interval of 8 in each class=x')

-A(1,:)=[8.5 16.5 24.5 32.5 40.5 48.5 56.5 64.5 72.5]

-disp('the second row denotes the no. of men or in other words frequency=f')

-A(2,:)=[2 24 21 18 5 3 5 8 2]

-disp('third row denotes f*x')

-for i=1:9

-  A(3,i)=A(1,i)*A(2,i);

-end

-disp('fourth row denotes d=(x-32.5)/8')

-for i=1:9

-  A(4,i)=(A(1,i)-32.5)/8

-end

-disp('fifth row denotes f*d')

-for i=1:9

-  A(5,i)=A(4,i)*A(2,i);

-end

-disp('sixth row denotes f*(d^2)  ')

-for i=1:9

-  A(6,i)=A(4,i)^2*A(2,i);

-end

-A

-b=0;

-disp('sum of all elements of sixth row=')

-for i=1:9

-  b+=A(6,i)

-end

-disp(b)

-f=0;

-disp('sum of all elements of second row=')

-for i=1:9

-  f+=A(2,i)

-end

-disp(f)

-disp('mean=')

-b/f

-d=0;

-disp('sum of all elements of fifth row=')

-for i=1:9

-  d+=A(5,i)

-end

-disp('mean wage=')

-32.5+(8*d/f)

-disp('standard deviation=')

+clc
+disp('the first row of A represents the mid values of wage classes having interval of 8 in each class=x')
+A(1,:)=[8.5 16.5 24.5 32.5 40.5 48.5 56.5 64.5 72.5]
+disp('the second row denotes the no. of men or in other words frequency=f')
+A(2,:)=[2 24 21 18 5 3 5 8 2]
+disp('third row denotes f*x')
+for i=1:9
+  A(3,i)=A(1,i)*A(2,i);
+end
+disp('fourth row denotes d=(x-32.5)/8')
+for i=1:9
+  A(4,i)=(A(1,i)-32.5)/8
+end
+disp('fifth row denotes f*d')
+for i=1:9
+  A(5,i)=A(4,i)*A(2,i);
+end
+disp('sixth row denotes f*(d^2)  ')
+for i=1:9
+  A(6,i)=A(4,i)^2*A(2,i);
+end
+A
+b=0;
+disp('sum of all elements of sixth row=')
+for i=1:9
+  b=b+A(6,i)
+end
+disp(b)
+f=0;
+disp('sum of all elements of second row=')
+for i=1:9
+  f=f+A(2,i)
+end
+disp(f)
+disp('mean=')
+b/f
+d=0;
+disp('sum of all elements of fifth row=')
+for i=1:9
+  d=d+A(5,i)
+end
+disp('mean wage=')
+32.5+(8*d/f)
+disp('standard deviation=')
 8*(b/f-(d/f)^2)
\ No newline at end of file