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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
commitb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch)
treeab291cffc65280e58ac82470ba63fbcca7805165 /149/CH23/EX23.2
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-rwxr-xr-x149/CH23/EX23.2/ex2.sce39
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diff --git a/149/CH23/EX23.2/ex2.sce b/149/CH23/EX23.2/ex2.sce
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+clc
+disp('the first row of A represents the mid values of weekly earnings having interval of 2 in each class=x')
+A(1,:)=[11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41]
+disp('the second row denotes the no. of employees or in other words frequency=f')
+A(2,:)=[3 6 10 15 24 42 75 90 79 55 36 26 19 13 9 7]
+disp('third row denotes f*x')
+for i=1:16
+ A(3,i)=A(1,i)*A(2,i);
+end
+disp('fourth row denotes u=(x-25)/2')
+for i=1:16
+ A(4,i)=(A(1,i)-25)/2
+end
+disp('fifth row denotes f*x')
+for i=1:16
+ A(5,i)=A(4,i)*A(2,i);
+end
+A
+b=0;
+disp('sum of all elements of third row=')
+for i=1:16
+ b+=A(3,i)
+end
+disp(b)
+f=0;
+disp('sum of all elements of second row=')
+for i=1:16
+ f+=A(2,i)
+end
+disp(f)
+disp('mean=')
+b/f
+d=0;
+disp('sum of all elements of fifth row=')
+for i=1:16
+ d+=A(5,i)
+end
+disp('mean by step deviation method=')
+25+(2*d/f) \ No newline at end of file