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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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treeab291cffc65280e58ac82470ba63fbcca7805165 /149/CH23/EX23.13
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+clear
+clc
+disp('the first row of A denotes the corresponding I.R. of students ')
+A(1,:)=[105 104 102 101 100 99 98 96 93 92];
+disp('the second row denotes the corresponding deviation of I.R.')
+for i=1:10
+ A(2,i)=A(1,i)-99;
+end
+disp('the third row denotes the square of corresponding deviation of I.R. ')
+for i=1:10
+ A(3,i)=A(2,i)^2;
+end
+disp('the fourth row denotes the corresponding E.R. of students ')
+ A(4,:)=[101 103 100 98 95 96 104 92 97 94];
+disp('the fifth row denotes the corresponding deviation of E.R. ')
+for i=1:10
+ A(5,i)=A(4,i)-98;
+end
+disp('the sixth row denotes the square of corresponding deviation of E.R. ')
+for i=1:10
+ A(6,i)=A(5,i)^2;
+end
+disp('the seventh row denotes the product of the two corresponding deviations ')
+for i=1:10
+ A(7,i)=A(2,i)*A(5,i);
+end
+A
+a=0;
+disp('the sum of elements of first row=a')
+for i=1:10
+ a=a+A(1,i);
+end
+a
+b=0;
+disp('the sum of elements of second row=b')
+for i=1:10
+ b=b+A(2,i);
+end
+b
+c=0;
+disp('the sum of elements of third row=c')
+for i=1:10
+ c=c+A(3,i);
+end
+c
+d=0;
+disp('the sum of elements of fourth row=d')
+for i=1:10
+ d=d+A(4,i);
+end
+d
+e=0;
+disp('the sum of elements of fifth row=e')
+for i=1:10
+ e=e+A(5,i);
+end
+e
+f=0;
+disp('the sum of elements of sixth row=d')
+for i=1:10
+ f=f+A(6,i);
+end
+f
+g=0;
+disp('the sum of elements of seventh row=d')
+for i=1:10
+ g=g+A(7,i);
+end
+g
+disp('coefficient of correlation=')
+g/(c*f)^0.5 \ No newline at end of file