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authorpriyanka2015-06-24 15:03:17 +0530
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+//CHAPTER 8- DIRECT CURRENT MACHINES
+//Example 9
+
+disp("CHAPTER 8");
+disp("EXAMPLE 9");
+
+//4 Pole 230 V lap wound shunt motor with 600 conductors. RPM 1800
+//VARIABLE INITIALIZATION
+P=4; //number of poles
+v_t=230; //in Volts
+I_l=52; //in Amperes
+Z=600; //tottal number of conductors
+r_f=115; //in Ohms
+d=30/100; //airgap diameter from cm to m
+l=20/100; //effective length of pole
+B=4100/10000; //flux density from Gauss to Wb/m^2
+
+//SOLUTION
+
+I_f=v_t/r_f; //I_f is same as I_sh
+I_a=I_l-I_f; // armature current
+ar=(%pi*d*l)/P; //area of pole
+phi=ar*B; //phi = flux
+A=P; //for lap winding
+T=(phi*Z*I_a)/(2*%pi*A); //Torque developed
+disp(sprintf("The torque developed in the motor is %.4f N-m",T));
+
+//The answer is different as 'A' has not been included in the denominator(in the book)
+
+//END
+