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+//CHAPTER 8- DIRECT CURRENT MACHINES
+//Example 19
+
+disp("CHAPTER 8");
+disp("EXAMPLE 19");
+
+//VARIABLE INITIALIZATION
+v_t=250;                    //in Volts
+r_a=0.5;                    //in Ohms
+r_f=250;                    //in Ohms
+N1=600;                     //in rpm
+I=21;                       //in Amperes
+r_s=250;                    //in Ohms
+
+//SOLUTION
+I_f1=v_t/r_f;
+I_f2=v_t/(r_f+r_s);
+I_a1=I-I_f1;
+// T is directly proportional to (Φ*I_a)
+// I_f is directly proportional to Φ
+// => I_f1*I_a1=I_f2*I_a2, therefore,
+I_a2=(I_f1*I_a1)/I_f2;      
+E_b1=v_t-(I_a1*r_a);
+E_b2=v_t-(I_a2*r_a);
+// E_b is directly proportional to (Φ*N)
+// (Φ*N) is directly proportinal to (I_f*N)
+// =>E_b1:E_b2=(I_f1:I_f2)*(N1:N2)
+N2=(I_f1/I_f2)*(E_b2/E_b1)*N1;
+N2=round(N2);              //to round off the value 
+disp(sprintf("The new speed of the motor is %d rpm",N2));
+
+//END