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+//CHAPTER 8- DIRECT CURRENT MACHINES
+//Example 16
+
+disp("CHAPTER 8");
+disp("EXAMPLE 16");
+
+//4 pole 250 V shunt motor
+//VARIABLE INITIALIZATION
+v_t=250;                   //in Volts
+P=4;                       //number of poles
+Z=500;                     //number of conductors
+r_a=0.25;                  //in Ohms
+r_f=125;                   //in Ohms
+phi=0.02;                  //in Wb
+I_l=14;                    //in Amperes
+A=2;
+rot_loss=300;              //rotational loss in Watts
+
+//SOLUTION
+
+//solution (i)
+I_f=v_t/r_f;                // field current
+I_a=I_l-I_f;                //armature current
+E_a=v_t-(I_a*r_a);          // induced emf
+N=(E_a*A*60)/(phi*Z*P);     //RPM
+N=round(N);                 //to round off the value of N
+disp(sprintf("(i) The speed is %d rpm",N));
+p_e=E_a*I_a;                //electromagnetic power
+w=(2*%pi*N)/60;             //speed in RPS
+T1=p_e/w;                   // Internal torque
+disp(sprintf("The internal torque developed is %.3f N-m",T1));
+
+//solution (ii)
+//shaft power
+p_o=p_e-rot_loss;           //power output
+disp(sprintf("(ii)The shaft power is %.0f W",p_o));
+T2=p_o/w;                   //shaft torque
+disp(sprintf("The shaft torque is %.2f N-m",T2));
+p_i=v_t*I_l;                // power input
+eff=(p_o/p_i)*100;          //efficiency
+disp(sprintf("The efficiency is %.2f %%",eff));
+
+//END 
+ 
+
+
+