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+//CHAPTER 8- DIRECT CURRENT MACHINES
+//Example 15
+
+disp("CHAPTER 8");
+disp("EXAMPLE 15");
+
+//230 V DC shunt motor
+//VARIABLE INITIALIZATION
+v_t=230;                    //in Volts
+I_a1=3.33;                  //in Amperes
+N1=1000;                    //in rpm
+r_a=0.3;                    //armature resistance in Ohms
+r_f=160;                    //field resistance in Ohms
+I_l=40;                     //line current in Amperes
+phi1=1;                     //in Wb (phi=1 is an assumption)
+phi2=(1-(4/100));           //in Wb (phi2=0.96 of phi1), as armature reaction reduces no load flux by 4%
+
+//SOLUTION
+
+//At no load
+E_a1=v_t-(I_a1*r_a);        //counter emf
+I_f=v_t/r_f;                //field current
+
+//At full load
+I_a2=I_l-I_f;
+E_a2=v_t-(I_a2*r_a);
+N2=(E_a2/E_a1)*(phi1/phi2)*N1;
+N2=round(N2);               //to round off the value
+disp(sprintf("The full load speed is %d rpm",N2));
+
+//END