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authorpriyanka2015-06-24 15:03:17 +0530
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+//CHAPTER 7- SINGLE PHASE TRANSFORMER
+//Example 19
+
+disp("CHAPTER 7");
+disp("EXAMPLE 19");
+
+//Open circuit and short circuit test on 10 kVA transformer 500/250 V 50 Hz single phase transformer
+//VARIABLE INITIALIZATION
+va=10000; //apparent power
+v1=500; //primary voltage in Volts
+v2=250; //secondary voltage in Volts
+f=50;
+//open circuit parameters
+Voc=500;
+Io=2;
+Wi=100; // watts HT side
+Woc=Wi; //just another nomenclature
+//short circuit test
+Vsc=25;
+Isc=20;
+Wc=90; // watts HT side
+//
+pf=0.8;
+//SOLUTION
+//open circuit
+phi0=acos(Woc/(v1*Io));
+Ic=Io*cos(phi0);
+Iphi=Io*sin(phi0);
+Rc=v1/Ic;
+X=v1/Iphi;
+disp("SOLUTION (a)");
+disp(sprintf("The value of Ic is %.2f Amp",Ic));
+disp(sprintf("The value of IΦ is %.2f Amp",Iphi));
+disp(sprintf("The value of Rc is %.0f Ohm",Rc));
+disp(sprintf("The value of X is %.0fΩ",X));
+//
+//short circuit
+phisc=acos(Wc/(Vsc*Isc));
+pf1=cos(phisc);
+R_e1=Vsc*pf1/Isc;
+Z_e1=Vsc/Isc;
+X_e1=sqrt(Z_e1^2-R_e1^2);
+disp(sprintf("The value of Power factor is %.3f",pf1));
+disp(sprintf("The value of Re1 is %.3f Ohm",R_e1));
+disp(sprintf("The value of Ze1 is %.3f Ohm",Z_e1));
+disp(sprintf("The value of Xe1 is %.3fΩ",X_e1));
+//
+//Regulation and efficiency
+//% Regulation
+I1=va/v1;
+phi=acos(pf);
+//R=ercosphi2+vx.sinphi2
+//E2=V2+I2.R
+%reg=(Isc*R_e1*pf+Isc*X_e1*sin(phi))*100/v1;
+disp("SOLUTION (c(i))");
+disp(sprintf("The percent regulation at full load is %.2f",%reg));
+//
+//Efficiency
+//full load output at pf=0.8
+Pout=va*pf;
+ironLoss=Wi;
+cuLoss=Wc;
+loss=ironLoss+cuLoss;
+Pin=Pout+loss;
+eff=Pout*100/Pin;
+disp("SOLUTION (c(ii))");
+disp(sprintf("The percent efficiency at full load is %.2f",eff));
+disp(" ");
+//
+//END