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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1445/CH3/EX3.9/Ex3_9.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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diff --git a/1445/CH3/EX3.9/Ex3_9.sce b/1445/CH3/EX3.9/Ex3_9.sce new file mode 100644 index 000000000..69339a32f --- /dev/null +++ b/1445/CH3/EX3.9/Ex3_9.sce @@ -0,0 +1,71 @@ +//CHAPTER 3- THREE-PHASE A.C. CIRCUITS +//Example 9 + +clc; +disp("CHAPTER 3"); +disp("EXAMPLE 9"); + +//VARIABLE INITIALIZATION +v_ab=400; //in Volts +v_bc=400; //in Volts +v_ac=400; //in Volts +z_ab=100; //in Ohms +z_bc=100; //in Ohms +z_ac=100; //in Ohms + +//solution (a) + +//function to convert from polar to rectangular form +function [x,y]=pol2rect(mag,angle); +x=mag*cos(angle); +y=mag*sin(angle); +endfunction; + +I_AB=v_ab/z_ab; +mag1=abs(real(I_AB)); +ang1=0; //I_AB is represented as mag1∠ang1 +I_BC=v_bc/z_bc; +ang2=-210*(%pi/180); //I_BC is represented as mag1∠ang2 +I_AC=v_ac/z_ac; +ang3=210*(%pi/180); //I_AB is represented as mag1∠ang3 +[x1,y1]=pol2rect(I_AB,ang1); +[x2,y2]=pol2rect(I_BC,ang2); +[x3,y3]=pol2rect(I_AC,ang3); +//let us consider values X1, Y1, X2, Y2, X3 and Y3 for the ease of calculation (these are not mentioned in the book) +X1=x1-x3; +Y1=y1-y3; +X2=x2-x1; +Y2=y2-y1; +X3=x3-x2; +Y3=y3-y2; +I_A=X1+(%i*Y1); +I_B=X2+(%i*Y2); +I_C=X3+(%i*Y3); + +//function to convert from rectangular to polar form +function [z,angle]=rect2pol(x,y); +z=sqrt((x^2)+(y^2)); //z is impedance & the resultant of x and y +if(x==0 & y>0) then angle=90; //in case atan=∞ +elseif(x==0 & y<0) then angle=-90 //in case atan=-∞ +else +angle=atan(y/x)*(180/%pi); //to convert the angle from radians to degrees +end; +endfunction; + +[mag4,ang4]=rect2pol(X1,Y1); +[mag5,ang5]=rect2pol(X2,Y2); +[mag6,ang6]=rect2pol(X3,Y3); +disp(sprintf("(a) The line current I_A is %f∠%f A",mag4,ang4)); +disp(sprintf("The line current I_B is %f∠%f A",mag5,(180+ang5))); +disp(sprintf("The line current I_C is %f∠%f A",mag6,ang6)); + +//solution (b) +//since power is consumed only by 100Ω resistance in the arm AB +r1=100; +p1=(I_AB^2)*r1; +p2=160000; +r2=p2/p1; +disp(sprintf("(b) The star connected balanced resistance is %d Ω",r2)); + +//END + |