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authorpriyanka2015-06-24 15:03:17 +0530
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+//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
+//Example 51
+
+disp("CHAPTER 2");
+disp("EXAMPLE 51");
+//
+//Given
+// admittance of branches are:
+//Y1=0.4+j0.6
+//Y2=0.1+j0.4
+//Y3=0.06+j0.23
+//
+//VARIABLE INITIALIZATION
+Y1=0.4+(%i*0.6); //admittance of 1st branch in Siemens
+Y2=0.1+(%i*0.4); //admittance of 2nd branch in Siemens
+Y3=0.06+(%i*0.23); //admittance of 3rd branch in Siemens
+
+//SOLUTION
+Y=Y1+Y2+Y3; // total admittance
+//function to convert from rectangular form to polar form
+function [Y,angle]=rect2pol(x,y);
+Y=sqrt((x^2)+(y^2));
+angle=atan(y/x)*(180/%pi); //to convert the angle from radians to degrees
+endfunction;
+[Y,angle]=rect2pol(real(Y),imag(Y));
+disp(sprintf("The total admittance of the circuit is %.3f S, %.2f degrees",Y,angle));
+z=1/Y;
+disp(sprintf("The impedance of the circuit is %.3f Ω, %.2f degrees",z,-angle));
+//
+//END