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+//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
+//Example 17
+
+disp("CHAPTER 2");
+disp("EXAMPLE 17");
+
+
+//Given
+//AC Voltage e(t)=141.4.sin (120.t) 
+//Current in the circuit is
+//i(t)=14.14.sin (120.t+7.07.cos (120.t+30)
+
+//VARIABLE INITIALIZATION
+e=141.4;                             //in Volts
+E=141.4/sqrt(2);                     //in Volts
+angle_E=0;                           //in degrees
+//i(t)=(14.14<0)+(7.07<120)
+i1=14.14;                            //in Amperes         
+angle_i1=0;                          //in degrees
+i2=7.07;                             //in Amperes
+angle_i2=120;                        //in degrees
+
+//SOLUTION
+//function to convert from polar form to rectangular form
+function [x,y]=pol2rect(mag,angle);
+x=mag*cos(angle*(%pi/180));          //to convert the angle from degrees to radians
+y=mag*sin(angle*(%pi/180));
+endfunction;
+[i1_x,i1_y]=pol2rect(i1,angle_i1);
+[i2_x,i2_y]=pol2rect(i2,angle_i2);
+i=(i1_x+i2_x)+(%i*(i1_y+i2_y));
+//function to convert from rectangular form to polar form
+function [mag,angle]=rect2pol(x,y);
+mag=sqrt((x^2)+(y^2));         
+angle=atan(y/x)*(180/%pi);           //to convert the angle from radians to degrees
+endfunction;
+[I,angle_I]=rect2pol((i1_x+i2_x),(i1_y+i2_y));
+I=I/sqrt(2);
+
+//solution (i)
+z=E/I;
+angle_z=angle_E-angle_I;
+[r,xc]=pol2rect(z,angle_z);
+f=50;
+c=1/(2*%pi*f*(-xc));
+disp(sprintf("(i) The value of resistance is %5.3f Ω",r));
+disp(sprintf("    The value of capacitance is %6.4f μF",c*10^6));
+
+//solution (ii)
+pf=cos(angle_z*(%pi/180));
+disp(sprintf("(ii) The power factor is %4.3f ",pf));
+
+//solution (iii)
+p=E*I*pf;
+disp(sprintf("(iii) The power absorbed by the source is %d W",p));
+
+//END