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+//CHAPTER 10- THREE-PHASE INDUCTION MACHINES
+//Example 8
+
+disp("CHAPTER 10");
+disp("EXAMPLE 8");
+
+//VARIABLE INITIALIZATION
+N_s=1200;                     //in rpm
+p_in=80;                      //in kW
+loss=5;                       //copper and iron losses in kW
+f_loss=2;                     //friction and windage loss in kW
+N=1152;                       //in rpm
+
+//SOLUTION
+
+//solution (a)
+p_rotor=p_in-loss;
+disp(sprintf("(a) The active power transmitted to rotor is %d kW",p_rotor));
+
+//solution (b)
+s=(N_s-N)/N_s;
+cu_loss=s*p_rotor;
+disp(sprintf("(b) The rotor copper loss is %d kW",cu_loss));
+
+//solution (c)
+p_m=(1-s)*p_rotor;
+disp(sprintf("(c) The mechanical power developed is %d kW",p_m));
+
+//solution (d)
+p_shaft=p_m-f_loss;          //output power
+disp(sprintf("(d) The mechanical power developed to load is %d kW",p_shaft));
+
+//solution (e)
+eff=p_shaft/p_in;
+disp(sprintf("(e) The efficiency of the motor is %f %%",eff*100));
+
+//END