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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS
+//Example 38
+
+disp("CHAPTER 1");
+disp("EXAMPLE 38");
+
+//VARIABLE INITIALIZATION
+I=2; //current source in Amperes
+r1=2; //in Ohms
+r2=1; //in Ohms
+r3=1; //in Ohms
+r4=2; //in Ohms
+
+//SOLUTION
+
+//Thevenin Equivalent circuit
+I1=1; //since there is equal resistance of 3Ω, hence, current=1A
+vth=(I1*r2)+(-I1*r4);
+req1=r1+r2;
+req2=r3+r4;
+rth=(req1*req2)/(req1+req2);
+disp("THEVENIN EQUIVALENT CIRCUIT IS-");
+disp(sprintf(" Thevenin voltage= %d V",vth));
+disp(sprintf(" Thevenin resistance= %f Ω",rth));
+
+//Norton Equivalent circuit
+v1=I/((1/r2)+(1/r4));
+v2=-I/((1/r3)+(1/r1));
+req1=r1+r2;
+req2=r3+r4;
+rn=(req1*req2)/(req1+req2);
+Isc=(v1/r4)+v2;
+disp("NORTON EQUIVALENT CIRCUIT IS-");
+disp(sprintf(" Norton current= %f A",Isc));
+disp(sprintf(" Norton resistance= %f Ω",rn));
+
+//END