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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+//initialisation of variables
+b= 1475.30 //kJ/kg
+b0= 144.44 //kJ/kg
+h2= 3448.6 //kJkg
+h1= 860.5 //kJ/kg
+k= 1.27
+k1= 1.34
+R= 8.314 //J/mol K
+hf= -393520 //kJ/kmol
+hg= 72596 //kJ/kmol
+Mc= 12 //kg
+n= 1.2 //moles
+n1= 3.76 //moles
+M= 32 //gms
+M1= 28 //gms
+M2= 44 //gms
+n2= 0.2 //moles
+n3= 4.512 //moles
+B1= 25592 //kJ/kmol C
+B2= 394360 //kJ/kmol C
+e= 0.008065
+//CALCULATIONS
+B= b-b0
+Q= h2-h1
+CpCO2= k*R/(k-1)
+CpO2= k1*R/(k1-1)
+Qcoal= (hg+hf)/Mc
+mcoal= Q/(-Qcoal)
+ncoal= mcoal/Mc
+r= (n*M+n1*M1)/Mc
+r1= (M2+n2*M+n3*M1)/Mc
+mair= r*mcoal
+mgas= r1*mcoal
+Bfuel= (B1-B2)*e
+Bnet= Bfuel+B
+p= B*100/(-Bfuel)
+//RESULTS
+printf (' change in energy= %.2f kJ/kg ',B)
+printf (' \n amount of air= %.3f kg/kg ',mair)
+printf (' \n amount of gas= %.3f kg/kg ',mgas)
+printf (' \n net change in energy= %.2f kg/kg steam ',Bnet)
+printf (' \n percent energy in original fuel= %.2f percent ',p)