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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 7.9
+// Power-Factor Correction with Parallel Loads
+V_l=780; // Generator Line voltage
+f=60; // Cyclic frequency (Hz)
+Z1_del= complex(30,60); // Load 1; balanced delta impedance
+Z2_wye=complex(30,0);// Load 2; balanced wye with impedance
+// Equivalent wye impedance of the delta load is ,
+Z1_wye=Z1_del/3;
+// Potential at equivalent neutral N1 of the delta load equals the potential at
+// N2 in the wye load
+// Hence from figure 7.24(b)
+Z_wye=(Z1_wye*Z2_wye)/(Z1_wye+Z2_wye);// Equivalent wye impedance per phase
+V_phi= V_l/sqrt(3); // Phase voltage from line voltage
+I_rms=V_phi/abs(Z_wye); // RMS current for one phase of the combined load
+P_phi=real(Z_wye)*I_rms^2; // Real power
+Q_phi=imag(Z_wye)*I_rms^2; // Reactive power
+// For balanced condition ,the three capacitor must be equal and arranged in a
+// delta or wye configuration
+C_del=Q_phi/(2*%pi*f*V_l^2); // For delta configuration
+C_wye= 3*C_del; // For wye configuration
+Q_C=-Q_phi; // Condition for connecting capacitor
+// Total Average power supplied by the generator
+P=3*P_phi;
+I_l=P/(sqrt(3)*V_l);// RMS line current
+disp(C_del,"Capacitance for power factor correction in delta configuration(in farad)=")
+disp(C_wye,"Capacitance for power factor correction in wye configuration(in farad)=")
+disp(P,"Total average power supplied by the generator(in Watt)=")
+disp(I_l,"RMS line current(in Amps)=")
+// NOTE- Computed Values for C_del and C_wye in Textbook is wrong.