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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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-rw-r--r--1430/CH2/EX2.6/exa2_6.sce15
-rw-r--r--1430/CH2/EX2.6/exa2_6.txt8
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diff --git a/1430/CH2/EX2.6/exa2_6.sce b/1430/CH2/EX2.6/exa2_6.sce
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+//Example 2.6
+// Amplifier with a Field-Effect Transistor
+//g_m=5*(10^-3); // Transconductance of voltage controlled current source
+
+function[v_out]=FET(v_in)
+g_m=5*(10^-3);
+v_g=(5/6)*v_in;// from figure 2.15,using Voltage divider in Left loop
+i_out=-g_m*v_g;// Using KCL in right Loop node
+v_out=(6*10^3)*i_out;// Output voltage of Amplifier
+endfunction
+
+// For Example take v_in= 1 volt
+V_in=1;
+V_out=FET(V_in);
+disp(V_out,"Output Voltage of this amplifier(in Volts)=")
diff --git a/1430/CH2/EX2.6/exa2_6.txt b/1430/CH2/EX2.6/exa2_6.txt
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+
+
+-->exec('C:\Users\sangeet\Documents\Scilab\Circuits\Chapter 2\exa2.6.sce', -1)
+
+ Output VOltage of this amplifier(in Volts)=
+
+ - 25.
+