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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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-rw-r--r--1430/CH2/EX2.11/exa2_11.sce10
-rw-r--r--1430/CH2/EX2.11/exa2_11.txt8
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diff --git a/1430/CH2/EX2.11/exa2_11.sce b/1430/CH2/EX2.11/exa2_11.sce
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+// Example 2.11
+// Superposition with a Controlled Source
+// From figure 2.22(b)
+i_1_1=30/(6*9+(4+2));// Contribution of 30-V Source
+// From figure 2.22(c), Applying KVL in bottom Loop we get,
+// 6*(9i_1_2)+4(i_1_2-3)+2*i_1_2=0
+i_1_2=0.2;
+// When Both independent sources active,the value of i_1 is given by the sum
+i_1=i_1_1+i_1_2;
+disp(i_1,"The Value of i_1 is(in Amps)=")
diff --git a/1430/CH2/EX2.11/exa2_11.txt b/1430/CH2/EX2.11/exa2_11.txt
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+
+
+-->exec('C:\Users\sangeet\Documents\Scilab\Circuits\Chapter 2\exa2.11.sce', -1)
+
+ The Value of i_1 is(in Amps)=
+
+ 0.7
+