diff options
| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1427/CH2/EX2.20/2_20.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
| download | Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.gz Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.bz2 Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.zip | |
initial commit / add all books
Diffstat (limited to '1427/CH2/EX2.20/2_20.sce')
| -rw-r--r-- | 1427/CH2/EX2.20/2_20.sce | 42 |
1 files changed, 42 insertions, 0 deletions
diff --git a/1427/CH2/EX2.20/2_20.sce b/1427/CH2/EX2.20/2_20.sce new file mode 100644 index 000000000..74ea96e56 --- /dev/null +++ b/1427/CH2/EX2.20/2_20.sce @@ -0,0 +1,42 @@ +//ques-2.20
+//Calculating theoretical quantity of air required and percentage of products of combustion and percentage of dry products when excess air is used and weight of dry gas on burning producer gas
+clc
+M=3.5;//Percentage of methane in producer gas
+CM=25;//Percentage of carbon monoxide in producer gas
+H=10;//Percentage of hydrogen in producer gas
+CD=10.8;//Percentage of carbon dioxide in producer gas
+N=50.7;//Percentage of nitrogen in producer gas
+v1=(M/100)*2;//volume of oxygen for methane (in kL)
+v2=(CM/100)*0.5;//volume of oxygen for carbon monoxide (in kL)
+v3=(H/100)*0.5;//volume of oxygen for hydrogen (in kL)
+V1=(M/100+CM/100)*1;//Volume of carbon dioxide as product (in kL)
+V2=(M/100)*2+(H/100)*1;//Volume of water as product (in kL)
+e=25;//Percentage of excess air used
+
+//Part (i)
+a=(v1+v2+v3)*(100/21);//theoretical amount of air
+printf("Theoretical quantity of air required is %.2f kL.\n",a);
+
+//Part (ii)
+V_CD=V1+CD/100;//Total volume of carbon dioxide (in kL)
+V_W=V2;//Total volume of water (in kL)
+V_N=a*(79/100)+N/100;//Total volume of nitrogen (in kL)
+V_T=V_CD+V_W+V_N;//Total volume (in kL)
+p1=(V_CD/V_T)*100;//Percentage of carbon dioxide
+p2=(V_W/V_T)*100;//Percentage of water
+p3=(V_N/V_T)*100;//Percentage of nitrogen
+printf(" The percentages of carbon dioxide, water and nitrogen in products of combustion are %.1f, %.2f and %.2f respectively.\n",p1,p2,p3);
+
+//Part (iii) (with excess air)
+V_N=a*(79/100)*(1+e/100)+N/100;//Total volume of nitrogen (in kL)
+V_O=(v1+v2+v3)*(25/100);//Total volume of oxygen (in kL)
+total=V_CD+V_N+V_O;//Total volume (in kL)
+p1=(V_CD/total)*100;//Percentage of carbon dioxide
+p2=(V_N/total)*100;//Percentage of nitrogen
+p3=(V_O/total)*100;//Percentage of oxygen
+printf(" The percentages of carbon dioxide, nitrogen and oxygen as dry products of combustion whenexcess air is used are %.1f, %.1f and %.2f respectively.\n",p1,p2,p3);
+
+//Part (iv)
+W=V_CD*1000*(44/22.4)+V_N*1000*(28/22.4)+V_O*1000*(32/22.4);//Weight of dry products (in g)
+printf(" The weight of dry products of combustion on burning producer gas is %.3f kg.",W/1000);
+
|