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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//ques-2.12
+//Finding volume of air required for combustion of a gas
+clc
+V=1;//Volume of gas (in kL)
+H=45;//Percentage of Hydrogen in gas
+N=4;//Percentage of Nitrogen in gas
+M=36;//Percentage of Methane in gas
+C=15;//Percentage of Carbo monoxide in gas
+v1=(H/100)*0.5;//Volume of Oxygen required for hydrogen (in kL)
+v2=(M/100)*2;//Volume of Oxygen required for methane (in kL)
+v3=(C/100)*0.5;//Volume of Oxygen required for carbon monoxide (in kL)
+V=(v1+v2+v3)*(100/21);//Volume of air required (in kL)
+printf("The volume of air required for combustion of gas is %.3f kL.\n",V);