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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//ques-18.44
+//Calculating enthalpy of the reaction and free energy change and entropy change at 925 K
+clc
+T1=925; T2=1000;//temperature (in K)
+K1=18.5; K2=9.25;//equikibrium constant
+H=(log10(K2/K1)*2.303*8.314*T1*T2)/(T2-T1);//enthalpy (in J/mol)
+G=-2.303*8.314*T1*log10(K1);
+S=(H-G)/T1;
+printf("The enthalpy of the reaction is %.1f kJ/mol, free energy change is %.1f kJ/mol and entropy change is %.1f J/K/mol.",H/1000,G/1000,S);