diff options
| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1415/CH1/EX1.3.2 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
| download | Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.gz Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.bz2 Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.zip | |
initial commit / add all books
Diffstat (limited to '1415/CH1/EX1.3.2')
| -rw-r--r-- | 1415/CH1/EX1.3.2/ex2.sce | 47 |
1 files changed, 47 insertions, 0 deletions
diff --git a/1415/CH1/EX1.3.2/ex2.sce b/1415/CH1/EX1.3.2/ex2.sce new file mode 100644 index 000000000..83d591c12 --- /dev/null +++ b/1415/CH1/EX1.3.2/ex2.sce @@ -0,0 +1,47 @@ +//Example 2 Page 81
+clc
+clear
+disp('a)')
+disp('two write the equation we need the two values one is the slope m and other is y intercept b')
+disp('the given points are')
+disp('(1,2),(3,-1)')
+y2=-1;//assigning the values
+y1=2;//assigning the values
+x1=1;//assigning the values
+x2=3;//assigning the values
+m=(y2-y1)/(x2-x1);//calculating m value
+mprintf("the slope of the line m = %f",m);//printing the valye m
+disp('we now find the y intercept b')
+b=y1-m*x1;//calculating the value b
+mprintf("the value of b = %f",b);//printing the valye b
+disp('substituting the values m and b in the equation we get the equation of the line is')
+disp('y=3x/2+7/2')
+
+disp('b)')
+// we dont have the two points here but we have the parallel line
+disp('the line parallel has the same slope ')
+//the given line is 3x+4y=5
+m=-3/4//assigning the slope value
+disp('we now have the slope and also the point (2,-2)')
+x1=2//assigning the value of x1
+y1=-2//assigning the value of y1
+b=y1-m*x1;//calculating b value
+disp(b,'b=-2-(-3/4)(2)=')
+disp('substituting the values m and b in the equation y=mx+c, we get' )
+disp('y=-3x/4-7/2')
+
+
+disp('c)')
+//since the line is horizontal it means that the slope m = 0
+disp('the point is (-9,5)')
+m=0//since the line is horizontal
+x1=-9//assigning the valye
+y1=5//assigning the value
+b=y1-m*x1;//calculating b value
+ disp(b,'5-(0)(-9)=')//displaying the value of b
+ disp('the line is y=5')//displaying line quation
+
+
+disp('d)')
+//since the line is vertical the slope is undefined
+disp('the line can be any solution so we take it as x=-9')
|